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2X + 4Y (dy/dx) = 4 4Y (dy/dx) = 4 - 2X dy/dx = (4 - 2X) / 4Y
To solve the equation, we need to try to make the second equation all in x first.From the first equation 2x-y=1,we could rewrite it into y=2x-1,Then we put y=2x-1 into the quadratic equation 10x2KMAnswered by KEYU M. • Maths tutor2953 Views
First, know the log rule: log(x) - log(y) = log(x/y)Second, know the log rule: log(a) + log(b) = log(ab)So, starting with the brackets: log(40) -log(20) = log(40/20) which is log(2).Now we have: log(2...
First we can try and factorise the expression:So we want to find 2 numbers that multiply to 6 and add to -5... after some thinking we get -2 and -3. The factorised expression is y=(x-2)(x...
5n+t= 21n-3t=9n= 9+3t5(9+3t)+t= 2145+15t+t= 2145+16t= 2116t= -24t= -1.55n-1.5= 215n= 22.5n= 4.5
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