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Find the centre coordinates, and radius of the circle with equation: x^2 + y^2 +6x -8y = 24

Firstly, rearrange the equation to group the 'x' terms together, and the 'y' terms together.x^2 + 6x + y^2 -8y = 24'Complete the square' on each of the x and y groups:(x + 3)^2 - 9 + (y - 4)^2 - 16 = 24Re...

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Answered by Sam N. Maths tutor
4328 Views

What is Integration

Integration can be conceptually understood in 2 different ways. firstly it is the reverse process of differentiation (Indefinite integration). Secondly it is used to work out the area under a curve (Defin...

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Answered by sulaiman n. Maths tutor
2874 Views

Differentiate y = arcsin(x) with respect to x

y = arcsin(x) implies sin(y) = x
Differentiating with respect to x gives: cos(y)*dy/dx = 1So: dy/dx = 1/cos(y)
Noting that cos(y) = sqrt(1 - sin^2(y)): dy/dx = 1/sqrt(1 - sin^2...

Answered by Maths tutor
3388 Views

Find the coordinates of the centre of the circle with equation: x^2 + y^2 − 2*x + 14*y = 0

method: complete the squares for (x^2 - 2x ) and ( y^2 + 14y ) using the formula (b/2)^2 (where the general equation is ax^2 + bx) so that the equation becomes ax^2 + bx ...

CA
Answered by Catherine A. Maths tutor
4020 Views

What is the value of x if (15*sqrt(x)) / sqrt(5) = 6*sqrt(5)

Note: sqrt means square root, and * means multiply method (overall aim is to make x the subject): multiply both sides by sqrt(5) to get: 15 * sqrt(x) = 6 * 5further expand the right hand sid...

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Answered by Catherine A. Maths tutor
3348 Views

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