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Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.

Firstly, we need to express 6cos(2x) + sin(x) in terms of sin(x) 6cos(2x) + sin(x) = 6cos(x+x) + sin(x) = 6cos2(x) - 6sin2(x) + sin(x) (applying cos(x+y) = cos(x)cos(y) - sin(x)sin(y...

DA
Answered by Dilan A. Maths tutor
3993 Views

A curve has equation x^2 +2xy–3y^2 +16=0. Find the coordinates of the points on the curve where dy/dx = 0.

x2 +2xy–3y2+16=0Differentiate the terms:x2 gives 2x2xy is differentiated by the product rule: vu' +v'u Make v = 2x and u = y, which gives 2x(dy/dx) + 2y3y2 give...

DA
Answered by Dilan A. Maths tutor
10776 Views

Solve the following simulatenous equation to find the values of both x and y: 5x+2y=16 3x-y=14

x=4, y=-2

OG
Answered by Oliver G. Maths tutor
2971 Views

Solve the following ((3x + 1)/2x ) = 4

3x + 1 = 4(2x) 3x + 1 = 8x 1 = 5x x = 1/5

BL
Answered by Benjamin L. Maths tutor
4136 Views

Identify and classify the stationary points of f using the second derivative test, where f is the function given below

f(x) = x4- 4x3+ 4x2
Given the function above, we need to find its stationary points. Its stationary po...

TG
Answered by Tinagrivea G. Maths tutor
1829 Views

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