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Differentiate with respect to x: i) y=x^3ln(2x) ii) y=(x+sin(2x))^3

i) There first step is to acknowledge the need for both product rule (d(uv)/dx=v.du/dx+u.dv/dx) and chain rule (dz/dx=dz/dy*dy/dx). Here, u=x^3 and v=ln(2x). Therefore, du/dx=3x^2 which is a standard diff...

EM
Answered by Edward M. Maths tutor
8687 Views

Factorise and solve x^2-8x+15=0

Factorise means we want to turn x2-8x+15=0 into the form (x+a)(x+b)=0. We need to find the two whole numbers 'a' and 'b' which equal -8 (from the -8x part) when added together,...

AC
Answered by Anokhi C. Maths tutor
4159 Views

Differentiate f(x) = (x+3)/(2x-5) using the quotient rule.

For a quotient f(x) = u(x)/v(x), the derivative is f'(x) = (vu'(x) - uv'(x))/v(x)2. Applying this to the given function, we find u(x) = x+3 and v(x) = 2x-5. So, u'(x) = 1 and v'(x) = 2...

SR
Answered by Sara R. Maths tutor
5295 Views

The first four terms of an arithmetic sequence are : 11, 17, 23, 29. In terms of n, find an expression for the nth term of this sequence.

An arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. We can work this out for the sequence 11, 17, 23, 29. ...

AG
Answered by Aman G. Maths tutor
17097 Views

Integrate 2x/(x^2+3) using the substitution u=x^2+3

u=x2 + 3

du/dx=2x

dx=du/2x

2x/(x2+3) dx becomes (2x/u) * (du/2x)

the 2x terms cancel out giving 1/u du

this integrates to ln(u)+c becoming ln(x

TS
Answered by Tom S. Maths tutor
13355 Views

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