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To do this we will assume sqrt(2) is rational, a fraction, which means: 21/2 = m/n; m,n belong to integers. Also, m/n is an irreductible fractionJCAnswered by Joao C. • Maths tutor3212 Views
Firstly we will start by expanding the brackets. We will do 2a + 23 for the first bracket, then we will do 5a + 5(-1) for the second bracket which will give us 2a + 6 + 5a - 5. We will ...
In order to solve a quadratic equation by factorisation you must first find the two numbers which add up to - 8 and multiply to get 15. We can do this by trial and error - first listing all of the pairs o...
This question uses a combination of standard differentiation and the product rule. The second part of the equation cos(x)sin(x) is the product of two funtions so the product rule must be used. Product rul...
When solving this quadratic inequality, we should use a three-step approach. The first step is to reformat the inequality to put one side equal to zero, which is the standard format of a quadratic equatio...
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