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y' = (2x)/(y+1). Solve for y.

y' = dy/dx = (2x)/(y+1) Separate x's and y's in this case.

y + 1 dy = 2x dx Now integrate both sides.

(y2)/2 + y = (2x2)/ 2 + C  Don't forget the constant. 

(y

DM
Answered by Daniel M. Maths tutor
3924 Views

Find the differential of (cos2x)^2

This is a question that can be answered in two ways: using the product rule and the rule for differentiating powers, we will do both to see how the two rules are equivalent. chain rule: split the function...

HC
Answered by Hoagy C. Maths tutor
6325 Views

How do you complete the square?

Completing the square is often useful when solving equations! An example: x+6x-7=0. Step 1) We want to move the constant to the right hand side: x2+6x=7. Step 2) Now, add the squar...

LW
Answered by Lisa W. Maths tutor
3819 Views

Simplify 125 ^ -2/3

= (1/125) ^ 2/3  = (1/5) ^ 2 = 1/25 To find a number to a negative power, you invert it (flip it so that 125 becomes 1/125) To find (1/125) ^ 2/3, find the cube root of 1/125 (=1/5) and then square it (=1...

ER
Answered by Ewen R. Maths tutor
6709 Views

Prove that the composite function fg(2)=-26 where f(x)=3x+1 and g(x)=1-5x

Here, f(x) and g(x) are functions of x, whose output depends on the value of x.

fg(2) means fg(x) where x=2.

Firstly, calculate g(2) and use this answer as the new value of x for f(x).

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AL
Answered by Alisha L. Maths tutor
12604 Views

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