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For a curve of gradient dy/dx = (2/(x^2))-x/4, determine a) d^2y/dx^2 b) the stationary point where y=5/2 c) whether this is a maximum or minmum point and d) the equation of the curve

a) Differentiating gives d2y/dx2=-4x-3-1/4

b) Let dy/dx=0 and rearrange to find x=2

c) Inserting x=2 into d2y/dx2=-4x-3-1/4 ...

KM
Answered by Katie M. Maths tutor
5527 Views

How does Euclid's algorithm give solutions to equations?

Euclid's algorithm is really useful to be able to, firstly, see if two numbers are co-prime, in other words to see if they share any common factors, but also to find solutions to equations. Say we have tw...

AR
Answered by Abby R. Maths tutor
1700 Views

Expand (x+2)(x-3)(x+4)^2

(x+2)(x-3)(x+4)^2 = (x^2 - x - 6)(x^2 + 8x + 16) = (x^4 + 8x^3 +16x^2 - x^3 - 8x^2 -16x - 6x^2 - 48x - 96) 

= x^4 +7x^3 + 2x^2 - 64x - 96)

RG
Answered by Roisin G. Maths tutor
2848 Views

Find ∫ ( 2x^4 - 4x^(-0.5) + 3 ) dx

When integrating, you need to add one to the power and divide the term by the power. We will consider each term individually, 2x4 will become (2x4+1)/(4+1) = (2x5)/5, -4x<...

RM
Answered by Rebecca M. Maths tutor
6826 Views

A curve has equation y = f(x) and passes through the point (4,22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7 use intergration to find f(x).

As f '(x) is the differential of f(x) we have to first integrate f '(x). To do this we take each term individually and integrate it. So starting with 3x2, to integrate a simple function of x li...

JO
Answered by Jonathan O. Maths tutor
7353 Views

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