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A curve C has equation: y = x^2 − 2x − 24x^1/2, x > 0; Find (i) dy/dx (ii) d^2y/dx^2

i) let dy/dx = ans, where ans = y, where you multiply the coefficients of each constant of x by the power and reduce the power by 1 in the equation ytherefore dy/dx = 2x - 2 - 12x-1/2ii) repeat...

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Answered by Charles H. Maths tutor
4322 Views

A teacher gives her students a maths test and they receive the scores: 4, 4, 7, 3, 9, 10, 5, 8. What was the mean score of the class?

To work out the mean, we first add up all of the scores so 4+4+7+3+9+10+5+8= 50. We then divide by the number of student who took the test, or the number of scores given, which is 8. Divide 50 by 8 to giv...

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Answered by Carmen L. Maths tutor
2384 Views

Solve x^2+6x+5=0

Use factorisation to solve this. You must find a pair of numbers that add to make 6 and multiply to make 5. In this question, 5 and 1 add to make 6 and they also multiply to make 5. So the factorised equa...

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Answered by Carmen L. Maths tutor
2708 Views

Given that y = arcos(x/2) find dy/dx of arccos(x/2) and hence find the integral from 0 to 1 of arcos(x/2)dx

a)    First we can rewrite y=arccos(x/2) as cosy = x/2 which allows us to use implicit differentiation to easily differentiate each side. Taking d/dx of each side gives u...

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Answered by Olivia P. Maths tutor
3204 Views

Find the tangent to the curve y=(3/4)x^2 -4x^(1/2) +7 at x=4, expressing it in the form ax+by+c=0.

In general, the equation of a line is y-y0=m(x-x0), where m is the gradient and (x0,y0) is a point on the line. We need to find the gradient and a point on our tangent. Step 1: Find gradient. Since our ta...

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Answered by Eleni P. Maths tutor
2820 Views

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