Top answers

Maths
All levels

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket...

CL
Answered by Clarence L. Maths tutor
3581 Views

What is a common factor?

A factor is a number that can be multiplied into another number with nothing left over. The factors of 9 are 1, 3, 9.A common factor is a number that is a factor of two different numbers. The factors of ...

TH
Answered by Tom H. Maths tutor
2041 Views

How do you solve an equation like: 5/(x+2) + 3/(x-3) = 2?

  1. Multiply every term by a denominator to eliminate it;5 + 3(x+2)/(x-3) = 2(x+2)5 + 3x+6/(x-3) = 2x+45(x-3) + 3x+6= (2x+4)(x-3)2) simplify5x-15+3x+6=2x2-12+4x-6x8x-9=2x2-12-2x2x<...
TH
Answered by Tom H. Maths tutor
5343 Views

Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = ...

KP
Answered by Kate P. Maths tutor
5066 Views

How would you solve (4y + 3)/5 + (3y+1)/2 = 4 for y?

The first step is to remove the fractions in the equation, as the equation is easier to solve when there are only whole numbers.To remove the first fraction we should times the entire equation by 5 ----&g...

NS
Answered by Nima S. Maths tutor
2388 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences