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Firstly, we need to factorise the equation:We can see (and are told) that the equation is quadratic and is therefore of the form ax^2 + bx + c. In our case, a=2, b=-5 and c=-3. We therefore expect two pai...

A simple way to prove this is to sub in the values that we are given. so f(x) will represent our equation x^3-3x+1 (that is f(x) = x^3-3x+1)f(-2) = -1 < 0f(-1) = 3 > 0The first thing we notice is th...

Start off with:x²+x=12Subtract 12 from both sides:x²+x-12=0Factorise:(x-3)(x+4)=0Solution is therefore:x=3 or x=-4

First factorise the equation : you need to find two value which multiply to give (4 x -6) = -24 and add to equal -5,these two numbers are -8 and 3. Then write the equation as follows:4x² - 8x...

Here we have to differentiate a constant raised to the power of a variable. To make it easier, let u=sinx and so our function can now be treated as y=a^u. Remembering that A = e^(LnA), a^u = e^(Ln(a^u)). ...