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Step 1: Simplify 3n + 2 ≤ 14 3n ≤ 12 n ≤ 4 and 6n > n^2 + 5 0 > n^2 -6...

x+10=0x= -10x-16=0x= 16

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

We must use the substitution method for this question because the first equation is a quadratic. Take the more simple equation (the second one), and use that to substitute the value for y in to the first ...

Using the product rule (u'v+v'u, where u and v are the chosen substitutes) to find the first derivative will be dy/dx=x'=2xe^(-2x)+x^(2)e^(-2x)(-2)=2xe^(-2x)(x-x^2). This will give the d...