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A circle has equation x^2+y^2+6x+10y-7=0. Find the equation of the tangent line through the point on the circle (-8,-1).

The circle can be written (x+3)2+(y+5)^2 = 41 and so has center (-3,-5).
The gradient through the center and the point (-8,-1) is;m = (-5+1)/(-3+8) = -4/5.
The tangent line is perpend...

RL
Answered by Rhianna L. Maths tutor
1018 Views

Solve the equation (2x-1)/3 + (x+2)/2 +x/6 = 8

The first thing you want to do is to get rid of the fractions,Multiplying everything by 6 will help you do this You must multiply every fraction by 6 and also everything you do to the left hand side...

NM
Answered by Niamh M. Maths tutor
5205 Views

given that f(x) = x^4 + 2x, find f'(x)

This is a simple differentiation question where we just differentiate by taking the power of the x and bringing that in front as a constant and then taking 1 off the power. So for the first term, x^4, we ...

SF
Answered by Sheheryar F. Maths tutor
4086 Views

A curve has an equation y=3x-2x^2-x^3. Find the x-coordinate(s) of the stationary point(s) of the curve.

The very first step in solving this problem is understanding that a stationary point is where the derivative of the curve, dy/dx (or in Newton’s notation y’), is equal to zero. This is because at stationa...

CG
Answered by Callum G. Maths tutor
4489 Views

Use the quotient rule to differentiate: ln(3x)/(e^4x) with respect to x.

Quotient rule: d(u/v)/dx = [(du/dx)v-u(dv/dx)]/v^2
u = ln(3x)
v = e^4x
Find du/dx using chain rule:
u = ln(z) ==> du/dz = 1/z
z = 3x ==> dz/dx = 3
(du/dz)(dz/dx) = ...

HT
Answered by Henry T. Maths tutor
4016 Views

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