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Step 1 differentiate substitution: du/dx = -2sin(2x)Step 2 rearrange for dx: dx=du/-2sin(2x)Step 3 substitute: integral= ∫u²sin³(2x).du/-2sin(2x)Step 4 get the integral in terms of u...

Step 1: Factorise the equation either directly or by using the quadratic formulae {[-b(+/-)sqrt(b^2-4ac)]/2a}. This equation can be factorised directly since 3*3=9 (for the last term on the RHS) and 3+3=6...

 y=x(x−1)y= x^2-xdy/dx= 2x-1

Example solve the following, equation 1: x²+2y=9 equation 2: y=x+3In this example we have to use substitution, therefore we sub in equation 2 into 1 to get the following x²+2(x+3)=9 ...

2^6 = 64 (2x2x2x2x2x2)6^2= 36 (6x6)
64+36= 100
Square root of 100= 10 (10x10=100)