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A-level: solve 8cos^2(x)+6sin(x)-6=3 for 0<x<2(pi)

8(1-sin^2(x))+6sin(x)-6=38(1-sin^2(x))+6sin(x)-9=08sin^2(x)-6sin(x)+1=0(2sin(x)-1)(4sin(x)-1)=02sin(x)-1=0 4sin(x)-1=02sin(x)=1 4sin(x)=1sin(x)=1/2 sin(x)=1/4x=(pi)/6 , 5(pi)/6 , 0.253 , 2.89
KM
Answered by Katie M. • Maths tutor
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Solve the equation 7^(x+1) = 3^(x+2)

1st we will log both sides of the equation7 (x+1) = 3 (x+2) becomes log7 (x+1) = log3 (x+2) NEXT we will use the power law which is log a (x) k =k log a (x)This turns log7 (x+1) = log3 (x+2) to (x+1) log7 = ...
AE
Answered by Anwulika E. • Maths tutor
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A circle with centre C has equation x^2 + y^2 +8x -12y = 12

Recognise that the form this question is a circleRemember alternate circle equation (x + a) 2 + (x + b) 2 = r 2 Where centre of circle (-a,-b) and r is the radiusTo get the right form use complete the square...
MG
Answered by Monique G. • Maths tutor
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The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.

3+4+5=12,72/12=6,3x6=18, 4x6=24,Area=1/2 x 18 x 24=216
KZ
Answered by Kamil Z. • Maths tutor
3071 Views

Make x the subject of the formula 3(2x – y) = ax – 4

Making x the subject of the formula means putting it into the form x = ..... As we can see there is an x on either side of the equation and brackets on the left side. Firstly according to BIDMAS we should ex...
JQ
Answered by Joseph Q. • Maths tutor
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