A-level: solve 8cos^2(x)+6sin(x)-6=3 for 0<x<2(pi)

8(1-sin^2(x))+6sin(x)-6=38(1-sin^2(x))+6sin(x)-9=08sin^2(x)-6sin(x)+1=0(2sin(x)-1)(4sin(x)-1)=02sin(x)-1=0 4sin(x)-1=02sin(x)=1 4sin(x)=1sin(x)=1/2 sin(x)=1/4x=(pi)/6 , 5(pi)/6 , 0.253 , 2.89

KM
Answered by Katie M. Maths tutor

5624 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

∫ (ln(x)/(x*(1+ln(x))^2) dx


Differentiate y = 7(x)^2 + cos(x)sin(x)


Find the exact gradient of the curve y=ln(1-cos2x) at the point with x-coordinate π/6


At time t = 0 a particle leaves the origin and moves along the x-axis. At time t seconds, the velocity of P is v m/s in the positive x direction, where v=4t^2–13t+2. How far does it travel between the times t1 and t2 at which it is at rest?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning