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Solve x^(2) + 7x + 6 = 0.

1) Factorise x 2 + 7x +6 Numbers that multiply to make +6: 6 and 1, -6 and -1, 3 and 2, -3 and -2 Which pair also add/subtract to make +7? 6 + 1 = 7 So factors are: (x+6)(x+1) 2) Solve value of x. (x+6)(x+1)...
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Answered by Rebecca H. • Maths tutor
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The curve y = 2x^3 -ax^2 +8x+2 passes through the point B where x = 4. Given that B is a stationary point of the curve, find the value of the constant a.

y=2x 3 - ax 2 + 8x +2. If we are told that B is the stationary point of the curve, then it is at that point where the gradient of the curve is equal to 0. In order to find the gradient of the curve at this p...
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Answered by Frazer M. • Maths tutor
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A and B are points on a circle, centre O. BC is a tangent to the circle. AOC is a straight line. Angle ABO = x°. Find the size of angle ACB, in terms of x. Give your answer in its simplest form. Give reasons for each stage of your working.

(This question is from the Edexcel Higher GCSE paper 2018) As BC is a tangent to the circle, we know that angle OBC must be a right angle (90 degrees)We also know that lines OA and OB are both the same lengt...
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Answered by Rachel T. • Maths tutor
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By completing the square, find the coordinates of the turning point of the curve with equation y = x^2 + 10x + 2

The equation is in the form ax^2 + bx + c, where a = 1, b = 10 and c = 2To complete the square, we write (x + b/2a)^2 + c - (b/2a)^2So here we would have (x + 5)^2 + 2 - 25Therefore completed square form is ...
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Answered by Niamh M. • Maths tutor
8433 Views

Solve x^2 - 3x - 10 = 0 for x by a) factorising and b) the quadratic equation. Then draw a graph of the function, marking when it touches each of the axes.

a) We factorise to find 2 numbers a and b in (x + a)(x + b) such that a + b = -3 and whose product is -10 (ab = -10). (x + 2)(x - 5) = 0 -> x = 5 or -2b) This is a direct application of the quadratic form...
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Answered by Joseph S. • Maths tutor
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