Solve the equation 7^(x+1) = 3^(x+2)

1st we will log both sides of the equation7^(x+1) = 3^(x+2) becomes log7^(x+1) = log3^(x+2)NEXT we will use the power law which is log_a (x)^k=k log_a (x)This turns log7^(x+1) = log3^(x+2)to (x+1) log7 = (x+2)log3NEXT we will multiply out the bracketsxlog7 + log7 = xlog3 + 2log3NEXT we will collect x terms on left and 'number' terms on rightxlog7 - xlog3 = 2log3 - log7NEXT we will factorisex(log7 - log3) = 2log3 - log7NEXT isolate xx = (2log3 - log7)/(log7 - log3) = 0.2966