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Maths
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Expand and simplify the following (x+4)(2x-3)=0

First of all you need to multiply the first value of each bracket, for example; x X 2x= 2x2 write this answer at the start of a new line Then multiply the first value of the first bracket by th...

AL
Answered by Autumn L. • Maths tutor
8081 Views

Factorize x^2 + 4x -5 and hence find the roots of the quadratic equation y = x^2 + 4x - 5.

First, identify the integer factors of the constant. In this case -5, has factors -1,5 and 1,-5. Now check to see if the sum of either pair is equal to the value of the coefficient of x. In this case, the...

AW
Answered by Alexander W. • Maths tutor
7064 Views

How can do you factorize the equation x^2+6x+8

Here, we see that the term in x in the equation is 6, so we start by looking for a perfect square where the second term would be 6 : we get 6/2 = 3 so we try (x+3)2. However, (x+3)2 = x

MS
Answered by Marine S. • Maths tutor
2997 Views

Differentiate with respect to x, x^2*e^(tan(x))

Use the product rule: d/dx(uv) = uv' + u'v, with u = x^2 and v = e^(tan(x)), so that u' = 2x and v' = sec^2(x) * e^(tan(x)), and so the answer is 2x * e^(tan(x)) + x^2 * sec^2(x) * e^(tan(x)) .

JH
Answered by Jakub H. • Maths tutor
5038 Views

Using partial fractions, find f(x) if f'(x)=5/(2x-1)(x-3)

First step: partial fractions 5/(2x-1)(x-3) 5=A(x-3)+B(2x-1) A=0 when x=3, so B=5/(2x3-1)=1 B=0 when x=1/2, so A=5/(0.5-3)=-2 So f'(x)=1/(x-3)-2/(2x-1) Second step: Integration f(x)= (integral)(1/(x-3))dx...

JF
Answered by Jasmin F. • Maths tutor
4802 Views

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