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As we know, to find a gradient in a linear function, we have to calculate the difference in the objective function (usually y) by the difference in the choice variable (commonly x), you may know this as r...
Integrating by parts is simple. Simply put the equation into two parts, U and dV/dx. When considering which part of the original function will be U and which part will take dV/dx, you should consider whic...
The first thing to do is draw a diagram to visualise the problem. Next we write down all the information the question gives us as well as which values we want to find. For this question it would be AAAnswered by Aysha A. • Maths tutor3780 Views
We're going to use the binomial expansion formula, which is a lot easier to remember than it looks: (a+b)n=C0*an*b0 + C1*a(n-1)...
Using the product rule, we find that dy/dx= dy/dt multiplied by dt/dx, where dt/dx is the reciprocal of dx/dt
dx/dt= 3t^2-10t+5, dy/dt= 4t
At t=3, dx/dt= 3(3)^2-10(3)+5=2, dy/dt= 4(3)= 12
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