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1. Move everything to the same side: 2x^3-12X^2-10x=0 2.Take out a factor of 2x: 2x(x^2-6x-5)=0 3.Complete the square on the quadratic: 2x[(x-3)^2-14]=0

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x ≤ -4.5

9^ (3x + 1)

We know that 3 to power of 2 equals 9.  3x3 = 3^2 = 9, 

= 3^ (2 * [3x + 1])

We simply the term because 2 * [3x + 1] = 6x + 2

= 3^ ( 6x + 2) 

This term is in ...

Firstly, solve 0=14-x^2 to find the horisontal distance to the edges of the tunnel. x1=sqrt(14), x2= -sqrt(14).

Integrate h=14-x^2 between x1 and x2 28*sqrt(14) -(2(sqrt(14)^3))/3. This is the requ...