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Max and Mins occur where the slope of a graph equals zero.
To find this, if we take the 1st derivative of a function and set the derivative equal to zero to solve for x.
The values we solv...
Multiply by 4-y => t(4-y)=y+2 Expand the brackets => 4t-ty=y+2 Get all the y's on the same side => 4t-2=ty+y Factor out the y => 4t-2=(t+1)y Divide by t+1 => (4t-2)/(t+1)=y
Notes; *Stationary (Turning) points are the points on the graph which are lowest or highest. (maximum or minima). *The gradient at a stationary point is zero. Steps: 1. Differentiate the function once to...
find dy/dx, algebraically manipulate the expression to get dy/dx in terms of x and y and then subsitute in the given point.
a) Firstly, differentiate x and y with respect to t.
Giving you dx/dt = 1/t and dy/dt = 12t2
dy/dx is found using the chain rule:
dy/dx = dy/dt x dt/dx = 12t3SWAnswered by Sara W. • Maths tutor3056 Views
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