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Prove that (sinx)^2 + (cosx)^2 = 1

We start with the definitions of sine and cosine, which are, respectively: sinx = opposite/hypoteneuse and cosx = adjacent/hypoteneuse. We then square the analyzed expressions to get the following:
...

Answered by Eno A. • Maths tutor

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A particle P moves with acceleration (-3i + 12j) m/s^2. Initially the velocity of P is 4i m/s. (a) Find the velocity of P at time t seconds. (b) Find the speed of P when t = 0.5

Solution:

V = V(0) + a*t

From the question: a = (-3i + 12j);
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Answered by Artur R. • Maths tutor
6100 Views

Using the quadratics formula find the two solutions to x^2 + 3x + 2 = 0.

x₁= (-b + (b²- 4ac)^1/2)/2a and x₂= (-b - (b²- 4ac)^1/2)/2a. So with the values a = 1, b = 3 and c = 2: x₁= (-3 + (3^{2 <...}

Answered by Rebecca D. • Maths tutor

3329 Views

Starting with x^2+2x+1=0 use the method of factorising to solve for x.

x²+2x+1=0, (x+1)(x+1)=0, (x+1)²=0. So x=-1

Answered by Rebecca D. • Maths tutor

3523 Views

How do you differentiate a function?

The differential of a function is defined by the expression: dy/dx = Lim(dx->0) of (f(x+dx)-f(x))/dx. For functions only involving powers of x, the differentioal can easily be calculated by timesing by...

Answered by Max H. • Maths tutor

3064 Views