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Use substitution u=cos(x) resulting in du=-sin(x)dx: ∫0π/2sin(x)cos(x)^2dx = ∫0π/2-u^2du = [-1/3 u^3]x=0x=π/2 = [-1/3 cos(x)^3]0BSAnswered by Benedek S. • Maths tutor7733 Views
Firstly, you should aim to eliminate one of the unknown values. As b is positive and negative in each equation, this would be a good value to eliminate. Both equations would have to be multiplied to cance...
There are a number of steps before sketching a graph. We will look over bits of theory and then do some examples (I'll show the examples in the online lesson space) First we have to find the x-intercept a...
Recall that the derivative of exp(x) is exp(x), but notice this question is slightly more complex due to the x^2 term. This is example of differentiationg composite functions, and so the chain rule is req...
The perimeter is the distance around the rectangle. A rectangle has 4 sides: 2 of them will be the length (8cm) and 2 of them the width (3cm). To get the perimeter, you add up 2 of the length and 2 of the...
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