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Express 9^(3x+1) in the form 3^y, giving "y" in the form "ax+b" where "a" and "b" are constants.

9= 32 so 93x+1 = 32(3x+1) = 36x+2

y= 6x+2 where a=6 and b=2 

LB
Answered by Laura B. Maths tutor
18310 Views

Express (16x+78)/(2x^2+25x+63) as two fractions

Firstly factorise the denominator to get (2x+7)(x+9). Then make the fraction equal to the seperate fractions with constants.

E.g 16x+78/2x^2+25x+63=A/(2x+7)+B/(x+9). then multiply accross by the de...

GD
Answered by Georgia D. Maths tutor
3078 Views

How do you expand (2x+9)^2?

(2x+9)2 = (2x+9)(2x+9) Use FOIL to expand these brackets: First - (2x+9)(2x+9) --> 4x2 Outside - (2x+9)(2x+9) --> 4x2 + 18x Inside - (2x<...

AM
Answered by Alec M. Maths tutor
7645 Views

5x - 2 > 3x + 11

Firstly we need to get all the x's on one side and the numbers on the other side. So if we add 2 to both sides we get 5x > 3x + 13. Now as we want the x's on the right hand side, we need to subtract bo...

SC
Answered by Sam C. Maths tutor
3404 Views

How do I solve two simultaneous equations?

Supposing we have two equations x+2y=5 and 3x-y=10 and we want to find x and y we can use the following techinque. Multiply both the RHS and the LHS of the second equation by 2, giving us 6x-2y=20. Then a...

TX
Answered by Theano X. Maths tutor
3253 Views

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