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Suppose we have two vectors U(a1,b1) and V(a2,b2). Hence, the distance between U and V will be given by the formula: d=sqrt((a1-b1)² + (a2-b2)²)

Factorise: (x-2)(x+4)(x-1)

Set equal to 0: (x-2)(x+4)(x-1) = 0

Points are (2,0) (-4,0) (1,0)

Step 1 : First we multiply both sides by 4, this is to eliminate /4 on the lhs(left hand side), and then we multiply the rhs(right hand side) by 4, this gives us (11-w) = 4(1+w) which is then equeal to 11...

This is a case of substitution. 2(3)+(7) =13

Before using a more complex formula it is better to know how to answer the question using a simpler method.

From the diagram we can see that this is a sector from a circle. We need to find out the ...