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I've been told that I can't, in general, differentiate functions involving absolute values (e.g. f(x) = |x|). Why is that?

When you differentiate a function which has only one parameter, like f(x), you are finding a new function, f'(x), which gives the gradient of your original function at every point. You'll probably remembe...

RW
Answered by Richard W. Maths tutor
2871 Views

What are the solutions of (x^3)+6 = 2(x^2)+5x given x = 3 is a solution?

Firstly we will put this into a form equal to zero, by rearranging to get x3-2x2-5x+6 = 0. This is because in order to solve a polynomial we first need to set it equal to zero. We no...

WB
Answered by William B. Maths tutor
5924 Views

When using the trapezium rule to approximate area underneath a curve between 2 limits, what is the effect of increasing the number of strips used?

Ideally to find the exact area under the curve, we would integrate the function and substitute in the bounds given. However, using the trapezium rule gives an approximation whereby using more trapezia inc...

MM
Answered by Manan M. Maths tutor
9230 Views

Solve the simultaneous equations: 6x + 2y = -3, 4x - 3y = 11

(1)   6x + 2y = -3

(2)   4x - 3y = 11

Multiply by 3 so that the coefficients of y are the same

3 x (1)    18x + 6y = -9

3 x (2)    8x - 6y = 22

Add these 2 together to e...

DH
Answered by David H. Maths tutor
5382 Views

Prove that sin(x)+sin(y)=2sin((x+y)/2)cos((x-y)/2)

We know that 1. sin(a+b) = sin(a)cos(b)+sin(b)cos(a) and 2. sin(a-b) = sin(a)cos(b)-sin(b)cos(a) Add equations 1. and 2. sin(a+b)+sin(a-b) = 2sin(a)cos(b)+sin(b)cos(a)-sin(b)cos(a) = 2sin(a)cos(b) Let x=a...

AV
Answered by Anna V. Maths tutor
33614 Views

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