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Using integration by parts, by substituting ln(3x) as u and x^8 as dv/dx, use the formula to plug in the values and complete the calculation to get (x^9)(ln(3x)-1/9)/9
We can see that we have the product of two different functions, and so we need to use the product rule. We will separate the function and label each part u and v for clarity. So we let u = 2ex ...
First, we must rearrange to give 2tan(θ) = 5x. Differentiate both sides with respect to x: 2sec2(θ)dθ/dx = 5 Use identity sin2(θ) + cos2(θ) = 1, dividing through by cosCWAnswered by Callum W. • Maths tutor4220 Views
s=distance/time = 100/12.45 =8.03m/s
With differentitaion you multiply the fatcor it's raised by and minus one from the order
e.g. y = x^n so y' = nx^(n-1)
So f'(x) = 3x^2 + 6x and f''(x) = 6x + 6
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