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The equation 2x^2 + 2kx + (k + 2) = 0, where k is a constant, has two distinct real roots. Show that k satisfies k^2 – 2k – 4 > 0

Two distinct real roots means that we can use b^2-4ac>0 relationship for any ax^2+bx+c equation. Apply the above gives, 4k^2 - 42(k+2)>0 Simplifying gives, k^2 - 2k -4 >0

AT
Answered by Andreas T. Maths tutor
11393 Views

How to find and classify stationary points (maximum point, minimum point or turning points) of curve.

To find the stationary points of a function we must first differentiate the function. The derivative tells us what the gradient of the function is at a given point along ...

CJ
Answered by Callum J. Maths tutor
17628 Views

Find the equation of the tangent to the curve y = (2x -3)^3 at the point (1, - 1), giving your answer in the form y = mx + c.

y = (2x -3)^3

y = (2x)^3 + 3.((2x)^2)(-3) + 3.(2x).(-3)^2 + (-3)^2 using Pascal's Triangle.

y = 8x^3 - 36x^2 + 54x - 27 

dy/dx = 24x^2 - 72x + 54

at point (1,-1); dy/dx = 24 -7...

RS
Answered by Robert S. Maths tutor
11894 Views

Find the first derivative of y=2^x

There is an initial subtle difficulty to this question, and it highlights understanding of the relationship between natural logarithms and the exponential function. One of the ways to solve this question,...

AM
Answered by Alex M. Maths tutor
3694 Views

What is Pythagoras' Theorem and how do you use it?

Pythagoras' Theorem: a2 + b2 = c2     where a, b, c relate to the sides of a right-angled triangle, and c is the hypoteneuse.

Use the equation to find the length on...

HS
Answered by Hermione S. Maths tutor
3058 Views

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