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Given the function y=(x+1)(x-2)^2 find i) dy/dx ii) Stationary points and determine their nature

Here we have a function made from the product of two functions, so we canuse the product differenciation rule.

y=uv  =>  dy/dx=udv/dx + vdu/dx

Therefore dy/dy=(x-2)^2 + 2(x-2)(x+1)

RB
Answered by Russell B. Maths tutor
4576 Views

Solve algebraically: 6a+b = 16 and 5a - 2b = 19

6a + b = 16 (1)

5a - 2b = 19 (2)

(1) x 2: 12a + 2b =32

(1) + (2): 12a + 2b + 5a - 2b = 32 + 19 = 51

17a = 51

a = 51 / 17 = 3

Substitue a = 3 back into (1): (6 x 3...

NR
Answered by Niva R. Maths tutor
2824 Views

Find the general solution to the differential equation '' (x^2 + 3x - 1) dy/dx = (2x + 3)y ''

Now although this might seem like quite a complex question at first, it's a little less intimidating when we take a while to look at it- you might notice that we can seperate x and y terms like so:
1...

ST
Answered by Sam T. Maths tutor
7156 Views

Solve 0=X^2 +5x +4

0= (x + 4)(x + 1)

x= - 4

x= - 1

RW
Answered by Rebecca W. Maths tutor
2622 Views

Differentiate y = lnx + 4x^2 + 3e^4x with respect to x

lnx differentiates to 1/x

4x^2 differentiates to 8x

3e^4x differentiates to 12e^4x

therefore the answer is: 1/x + 8x + 12e^4x

DS
Answered by Dhylon S. Maths tutor
3762 Views

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