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John ran a 450m race (2sf) in a time of 62 seconds (nearest second). Calculate the difference between his maximum and minimum average speed. (3sf)

S=D/T Max= 455(upper bound)/61.5(lower bound)= 910/123 m/s Min= 445(lower bound)/62.5 (upper bound) = 178/25 m/s Max - Min= 856/3075 m/s

CR
Answered by Christopher R. Maths tutor
4178 Views

There are 45 pupils in a class, 1/9 travel to school by train, 2/5 travel to school by car, 2/9 take the bus. Find how many students walk

First the number of children that travel by train can be found by dividing 45 by 9 to give 5. Since we know that double as many take the bus, as 2/9 is the double of 1/9,5x2=10 children take the bus. Then...

KS
Answered by Karina S. Maths tutor
14348 Views

x is inversely proportional to P. When P = 6, x =2. What does x = when P = 4?

We know x is inversely proportional to P, so immediately we know their relationship is of the form x = k/P , where k is a constant. We are also given some conditions we can use to solve for k: when x = 2,...

AS
Answered by Alec S. Maths tutor
3868 Views

Split the following expression into partial fractions of the form A/(x-3) + B/(4x+2) : (19x-15)/(4x+2)(x-3)

Set the expression equal to the form required in the solution. Multiply both sides by (4x-2)(x-3) to get rid of the denominator and acquire an expression of the form: 19x-15 = A(4x+2) + B(x-3). From here ...

AS
Answered by Alec S. Maths tutor
4734 Views

How do you simplify (3x-3)/(x-1)?

The important thing here is to try and find the bottom bracket in the top bracket ie the numerator

Notice that (3x-3) can be divided by 3 and therefore (3x-3) can be written as 3 multiplied by (x-1...

LO
Answered by Liam O. Maths tutor
8586 Views

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