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Firstly notice that to find a stationary point of a curve with an equation, the best first step is often to differentiate the expression. Then solve the equation for x when dy/dx = 0. In this case the y e...

8x² + 6x + 1. This is a quadratic equation as the highest power of x is to the power of 2.A quadratic is written in the form: ax² + bx + c. The coefficient of the x² term ...

As x=3 is a solution, (x - 3) is a factor of f(x) = 2x³- 8x²+ 7x - 3 = 0 ie. 2x³- 8x²+ 7x - 3 = (x - 3)(Ax² + Bx + C) where A,B,C are constants to be...

So what we need to do is work out what x is when y is equal to 11.Firstly, we would rearrange the equation so that x is the subject and to do this we subtract 5 from both sides.Thisgives us y-5 =2x. Divid...

3x+1/(x+1)(2x+1)=A/(x+1) + B/(2x+1)Multiply equation by (x+1) and (2x+1) to get:3x+1= A(2x+1) + B(x+1)Let x=-1 (x+1=0 so x=-1) sub into new equation. -2= A(-1) + B (x+1)-2=-AA=2Let x=-1/2 and sub into sam...