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Use Pythagoras theorem to work out the hypotenuse when the adjacent length of a triangle is 3 and the opposite side is 4.

using the Pythagoras formula: a^2 + b^2 = c^2 the longest measurement is always the hypotenuse due to the orientation of a triangle and so c is the hypotenuse leaving the a and b to be the two measuremen...

Answered by Saif S. • Maths tutor

2264 Views

If f(x) = 3x +x^2, what is f(-2)?

f(-2) = 3(-2) + (-2)²= -6 + 4 = 2First you need to substitute -2 for each value of x in the function. Then you need to simplify the expression by multiplying -2 by 3 and by squaring -2. (Hint...

Answered by William B. • Maths tutor

4956 Views

Add the fractions 2/5 + 3/7.

We must find a common denominator between the fractions to be able to add them (the bottom numbers must be the same). A common denominator of 5 and 7 is 35. To get to 35 from 5 we multiplied by 7, therefo...

Answered by Alex L. • Maths tutor

14991 Views

Find the length of AB from the right-angle triangle ABC. Angle ACB = 40 degrees and side BC = 15cm.

Label each of the sides using the angle BCA. Therefore, AC = Adjacent, BC = Hypotenuse and AB = Opposite. Use the anagram SohCahToa to identify the side that we have (BC) and the side we are looking for (...

Answered by Alex L. • Maths tutor

3898 Views

Find the coordinates of the stationary point of y = x^2 + x - 2

At a stationary point, the gradient/slope of the graph is 0. To find the gradient of y, we differentiate with respect to x.This gives us dy/dx = 2x + 1. Since we want to find where the gradient is 0, we s...

Answered by Martin C. • Maths tutor

4716 Views