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A = {multiples of 5 between 14 and 26}. B = {odd numbers between 14 and 26}. List the members of A∪B and A∩B.

First write down explicitly what the elements of A and B are.A={15,20,25}, B={15,17,19,21,23,25}.
Remember ∪ means OR. So A ∪ B is the set of items which are in either A OR B. This is {15,17,19,21,23...

LP
Answered by Luke P. Maths tutor
14201 Views

∫2x(x+2)^(1/2) dx evaluated from 0->2

First make a substitution so we can apply the power rule ∫xn dx = (xn+1)/(n+1) + C more simply. Can see u=x+2 means (x+2)1/2 -> u1/2 and so will help us appl...

LP
Answered by Luke P. Maths tutor
11020 Views

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket...

CL
Answered by Clarence L. Maths tutor
3414 Views

What is a common factor?

A factor is a number that can be multiplied into another number with nothing left over. The factors of 9 are 1, 3, 9.A common factor is a number that is a factor of two different numbers. The factors of ...

TH
Answered by Tom H. Maths tutor
1806 Views

How do you solve an equation like: 5/(x+2) + 3/(x-3) = 2?

  1. Multiply every term by a denominator to eliminate it;5 + 3(x+2)/(x-3) = 2(x+2)5 + 3x+6/(x-3) = 2x+45(x-3) + 3x+6= (2x+4)(x-3)2) simplify5x-15+3x+6=2x2-12+4x-6x8x-9=2x2-12-2x2x<...
TH
Answered by Tom H. Maths tutor
5151 Views

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