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Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = ...

KP
Answered by Kate P. Maths tutor
5258 Views

How would you solve (4y + 3)/5 + (3y+1)/2 = 4 for y?

The first step is to remove the fractions in the equation, as the equation is easier to solve when there are only whole numbers.To remove the first fraction we should times the entire equation by 5 ----&g...

NS
Answered by Nima S. Maths tutor
2543 Views

What is the difference between '<' and '≤'?

  1. 'x < 4' simply means that x is less than 4.2) However, x ≤ 4 means that it is less than or equal to 4. So if you have x = 3, 2, 1, 0 then the first term, 'x < 4' appliesbut if...
TH
Answered by Tom H. Maths tutor
3539 Views

Find the equation of the normal of the curve xy-x^2+xlog(y)=4 at the point (2,1) in the form ax+by+c=0

differentiating: xy'+y-2x+(x/y)y'+log(y)=0rearranging: y'=y(2x-y-log(y))/x(1+y)at (2,1): y'=3/4 so gradient of normal at (2,1) is -4/3so the equation of the normal is y-1=(-4/3)(x-2)which is equivalent to...

SL
Answered by Sam L. Maths tutor
3131 Views

Solve the simultaneous equations y = x^2 +3x and y = x+8

Because both of the equations are equal to y, the first thing we do is make them equal to each other:x^2 + 3x= x + 8We then want to rearrange the equation so that everything is on the same side of the equ...

JW
Answered by Jessica W. Maths tutor
3933 Views

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