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Integrate Sin^2(x)

(using double angle formula)Sin^2(x)=1/2-(Cos(2x)/2)
So the Integral is 1/2(x-1/2Sin(2x))which simplifies to x/2 - 1/2Sin(x)Cos(x)

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Answered by Alex R. Maths tutor
3372 Views

The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Work out the area of the triangle.

Consider a right angled triangle, it has perimeter of 72cm. Let's label the three sides a, b and c.Therefore, a + b + c = 72cm.Also, we know that a:b:c = 3:4:5Therefore we can say that a = 3x, b = 4x, c =...

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Answered by Dilan A. Maths tutor
2514 Views

Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.

Firstly, we need to express 6cos(2x) + sin(x) in terms of sin(x) 6cos(2x) + sin(x) = 6cos(x+x) + sin(x) = 6cos2(x) - 6sin2(x) + sin(x) (applying cos(x+y) = cos(x)cos(y) - sin(x)sin(y...

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Answered by Dilan A. Maths tutor
3891 Views

A curve has equation x^2 +2xy–3y^2 +16=0. Find the coordinates of the points on the curve where dy/dx = 0.

x2 +2xy–3y2+16=0Differentiate the terms:x2 gives 2x2xy is differentiated by the product rule: vu' +v'u Make v = 2x and u = y, which gives 2x(dy/dx) + 2y3y2 give...

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Answered by Dilan A. Maths tutor
10543 Views

Solve the following simulatenous equation to find the values of both x and y: 5x+2y=16 3x-y=14

x=4, y=-2

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Answered by Oliver G. Maths tutor
2873 Views

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