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The equation of line A is (x)^2 + 11x + 12 = y - 4, while the equation of line B is x - 6 = y + 2. Find the co-ordinate(s) of the point at which lines A and B intersect.

While this question may seem complicated, this question is simply asking you to solve the equations of these two lines as simultaneous equations. Line A: x² + 11x + 12 = y - 4 --> x

Answered by Ann A. • Maths tutor

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Solve the following quadratic equation: 2x^2 - 5x - 3 = 0

Firstly, we need to factorise the equation:We can see (and are told) that the equation is quadratic and is therefore of the form ax^2 + bx + c. In our case, a=2, b=-5 and c=-3. We therefore expect two pai...

Answered by Jacob A. • Maths tutor

3879 Views

The equation " x^3-3x+1=0 " has three real roots. Show that one of the roots lies between −2 and −1

A simple way to prove this is to sub in the values that we are given. so f(x) will represent our equation x^3-3x+1 (that is f(x) = x^3-3x+1)f(-2) = -1 < 0f(-1) = 3 > 0The first thing we notice is th...

Answered by James B. • Maths tutor

7600 Views

Solve x^2 + x=12 by factorising

Start off with:x²+x=12Subtract 12 from both sides:x²+x-12=0Factorise:(x-3)(x+4)=0Solution is therefore:x=3 or x=-4

Answered by Duwan B. • Maths tutor

2824 Views

Solve the quadratic equation 4x^2 - 5x -6 = 0

First factorise the equation : you need to find two value which multiply to give (4 x -6) = -24 and add to equal -5,these two numbers are -8 and 3. Then write the equation as follows:4x²- 8x...

Answered by Katie S. • Maths tutor

6985 Views