Search over 10,000 free study notes

Thinking about the normal, it is a line which cuts the curve at right angles, and so will have the form y = mx + c. Now at the point where x = 1, we know the y value from the curve's equation is y = 2(1)<...

Step 1: Recognise the quadratic term, this cannot be solved through elimination. Therefore we must need to use substitution. Substitute y = x + 3 into the quadratic. Gives x + 3 = x² + 3xStep 2...

Step 1: Simplify 3n + 2 ≤ 14 3n ≤ 12 n ≤ 4 and 6n > n^2 + 5 0 > n^2 -6...

x+10=0x= -10x-16=0x= 16

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60