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Find the equation of the tangent to the curve y = 4x^2 (x+3)^5 at the point (-1, 128).

y = 4x2(x+3)5 . Use the product rule to find the first derivative of the curve, 8x(x+3)5 + 20x2(x+3)4 , and substitute x = -1 to find the gradient at...

JG
Answered by Jack G. Maths tutor
3225 Views

How do I use the product rule for differentiation?

You should use the product rule when you have a function f(x), which you can't differentiate straight away. But which can be written in the form f(x)=g(x)h(x), where g(x) and h(x) are functions that you d...

HV
Answered by Harry V. Maths tutor
2657 Views

Simultaneous equation: (x-3y)=9,(2x+3y)=0

Using one of the equations we express either x in the form of y, or y in the form of x. We then put this expression of x/y into the other equation. This allows us to calculate the numerical values of both...

KT
Answered by Kerushan T. Maths tutor
3634 Views

y = 4(x^3) + 7x ... Find dy/dx

This is a simple differentiation question. To start, you need to know the general method of differentiation. This is:
if y = Axb then dy/dx = (A*b)x

EE
Answered by Emilio E. Maths tutor
3125 Views

ABCD is a rhombus on a graph. B(7,10). AC: y=7-4x. Find an equation for DB in the form tx+py+r=0 where t,p&r are integers.

AC and DB must be perpendicular therefore m1m2 = -1. (we can work out the gradient of DB)-4m2 = -1 -----> m2 = 1/4The equation of a line is y-y...

AL
Answered by Alexander L. Maths tutor
2531 Views

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