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Integrate ln(x)

Take ln(x) = 1 * ln(x) and integrate by parts. Let u = ln(x) and dv/dx = 1 such that du/dx = 1/x and v = x. Using the integrating by parts formula, you get x ln(x) - integral(1) = x ln(x) - x + c.

JY
Answered by Jason Y. Maths tutor
3699 Views

A ball of mass m moves towards a ball of mass km with speed u. The coefficient of restitution is 0. What is the final velocity if the first ball after the collision.

Coefficient of restitution is defined as the ratio of the relative speed of separation of the balls to the relative speed of approach. A ratio of 0 means that the speed of separation has a value of zero a...

SE
Answered by Susannah E. Maths tutor
3072 Views

Differentiate cos^2(x)

Using the chain rule, Let y=cos2(x)Let u=cos(x)y=u2dy/du=2udu/dx=-sin(x)dy/dx=dy/du*du/dx=-2sin(x)cos(x)

MB
Answered by Manish B. Maths tutor
5976 Views

Find the equation of the tangent to the curve x^3+yx^2=1 at the point (1,0).

We can find the gradient of a tangent to a curve at a point by finding dy/dx at x=1.Firstly we can rearrange the equation of the curve for y.(1) yx^2=1-x^3(2)y=x^{-2}-xThen we can differentiate the equati...

OG
Answered by Ollie G. Maths tutor
3139 Views

An 1kg ball collides normally with a fixed vertical wall. Its incoming speed is 8 m/s and its speed after the collision is 4 m/s . Calculate the change in momentum of the particle. If the collision lasts 0.5 s calculate the impact force.

Consider two scenarios before and after. Before there is a velocity of 8m/s (with right being positive) and mass 1kg. after there is a mass of 1kg and a velocity of -4 m/s as right is positive and it boun...

AD
Answered by Adam D. Maths tutor
3791 Views

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