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Write down 56 as the product of its prime factors.

56 / 2 = 2828 / 2 = 1414 / 2 = 77 / 7 = 1so, 56 = 2x2x2x7 = 23x7Example of a non calculator GCSE paper question, higher tier

MA
Answered by Mehdi A. Maths tutor
6777 Views

a) Express 4(cosec^2(2x)) - (cosec^2(x)) in terms of sin(x) and cos (x) and hence b) show that 4(cosec^2(2x)) - (cosec^2(x)) = sec^2(x)

A) 4(cosec2(2x)) - (cosec2(x)) = 4/(sin2(2x)) - 1/(sin2(x)) = 4/[(2 sin(x) cos(x))2] - 1/(sin2(x)) B) 4/[(2 sin(x) cos(x))2] - ...

MR
Answered by Mario R. Maths tutor
20409 Views

A curve has equation y = f(x) and passes through the point (4, 22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7, use integration to find f(x), giving each term in its simplest form

As we are given the derivative of f(x), we first need to integrate this derivative to obtain the function, f(x). Using the standard integration formula, ∫ x^n dx = (1/n+1)(x^(n+1)) +c, integrate each term...

AC
Answered by Alex C. Maths tutor
8427 Views

Simplify fully: (24 - √ 300)/(4√ 3 - 5). Give your answer in the form a√ b where a and b are integers and find the values of a and b.

rationalise the denominator (remove the surds) by multiplying by a fraction = 1, known as the rationalising factor = (24 - √ 300)/(4√ 3 - 5) * (4√ 3 + 5)/(4√ 3 + 5) = (24 - √ 300)(4√ 3 + 5)/(48 - 25) = (2...

AL
Answered by Aloysius L. Maths tutor
6645 Views

Solve the simultaneous equations. 2x + y = 18 . x - y = 6

x = 6 + y
2(6+y) + y = 18
12+2y+y = 18
3y = 18-12
3y=6
y = 6/3 = 2. So y = 2 if y = 2 then x is = ?
x - y = 6 so, x-2 = 6
so x is 6+ 2 = 8
x = 8 and y = 2<...

OO
Answered by Olufunke O. Maths tutor
3285 Views

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