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To start off, let's write the equation involving these three objects: Mv = xv. Now, looking at the first form of the equation, we don't want any eigenvector to have all its entries be zero, or else the ei...
3a+2b = 178a-2b = 60We are going to solve this using the elimination method. This means that we are going to eliminate the variable (or letter) that has the same value in each equation. In this case it is...
x2 + 10x + 24 = 0First we must factorise the equation, which means put it into brackets. To do this we must find two numbers which multiply to equal 24 and add together to make 10. The on...
A + B + C = £722A = B3B = C0.5 B + B + 3B = £724.5 B = £72B = £16C = £48
The first thing to do is write down y’ and y’’ neatly since these are the main two equations we will be working with… y’ = 2x2 – x – 3 & y’’ = 4x – 1… To find the stationary point we must f...
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