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f^-1(x)= 5(x-1)

y =x/3 - 2a
y + 2a = x/3
3y+6a = x

Increase the power by one and divide by the new powere.g. integrate x²+5x + 3Answer: x³/3 + 5x²/2 + 3x

(2x)/2= 2x^-2d2y/dx2= -4x^-1 - 1/4

So we have to integrate these 3 terms one by one. To integrate 2x⁵ you add 1 to the power of x, so that becomes 6, you then divide the coefficient by the new power of x. So 3/6=1/2 giving the i...