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A right-angled triangle has perpendicular sides of length 6cm and 8cm, and a hypoteneuse of 2y cm. Find the length of y.

By Pythagoras' Theorem:(2y)²= 6²+ 8²4y²= 36 +64y² = 9 + 16y² = 25y = ±5However, dimensions can only have a positive value. Therefore ...

Answered by Emmanuel S. • Maths tutor

2750 Views

Solve the simultaneous equations to find x and y: 3y - x = 12 y + 2x = -3

3y - x = 12 (1)y + 2x = -3 (2)multiply equation (2) by 3: 3y + 6x = -9 (3)subtract equation (1) from equation (3): 3y + 6x - 3y + x = -9 -12 7x = -21 x = -3substitute x into equation (2): y -6 = -3 y = 3a...

Answered by Chloe G. • Maths tutor

3597 Views

Differentiate y = x^3− 5x^2 + 3x

the rule for differentiating in terms of x is to multiply by the power then decrease the power by one. So going through the equation x^3 will be multiplied by 3 and go to x^2 so will be 3x^2. Then its imp...

Answered by Georgia D. • Maths tutor

6931 Views

I have £300 I want to split between my daughters Megan, Danni and laura in the ratio 3:4:1 respectively. How much money will Danni get?

Firstly, we need to add up how many 'parts' this money is being split into by adding the ratio, 3+4+1 = 8 parts. Now we need to calculate how much one part is equal to by splitting our £300 into the 8 par...

Answered by Holly M. • Maths tutor

2749 Views

Expand the following quadratic expression: (2x+4)(x-5)

Multiply the first terms in both brackets:2xx= 2x²
Next multiply the first term of the first bracket and the second term of the second bracket:2x-5= -10x
Multiply...

Answered by Meera P. • Maths tutor

5141 Views