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Solve the simultaneous equations: (a) y - 2x = 6; (b) y+2x = 0.

rearrange equation (a) to be: y = 6 + 2x. Substitute this into equation (b) to get: (6 + 2x) + 2x = 0 rearrange this to get: 6 + 4x = 0. Simplify to get x = -(6/4). Get the value for x to be: x = -1.5. subst...
FM
Answered by Faizan M. • Maths tutor
11328 Views

May you please help me solve these algebra problem set ?

I would go through one of the problem on the interactive board with the student and ask them to try next question alone.
TM
Answered by Tara M. • Maths tutor
3542 Views

Find the minimum value of the function, f(x) = x*exp(x)

The minimum value lies where the tangent to the curve has a gradient of zero and the curve approaching from both directions increases in value. This is done by finding the first and second derivatives of the...
RT
Answered by Robin T. • Maths tutor
4200 Views

1a) Simplify 2a^3 x a^5 1b) (4x^2)^3 1c) 2(3y+1) - 3(y-4)

1a) To simplify this into one expression you first multiply together the co-efficients, therefore 2a x a = 2a. Then for indices when they are multiplied together you add them, so the simplification would be ...
FI
Answered by Freddie I. • Maths tutor
4624 Views

Given the function f(x) = 2x^2 + 3.When f(x) = 53 find both values of x

Sub in f(x)=53 into equation. So you have 53=2x^2+3, deduct 3 from both sides to get 50=2x^2 and then divide each side by 2 to get 25=x^2 and finally square root both sides to get x=5 or x=-5.
JW
Answered by Jack W. • Maths tutor
6600 Views