Solve the simultaneous equations: (a) y - 2x = 6; (b) y+2x = 0.

  • rearrange equation (a) to be: y = 6 + 2x. Substitute this into equation (b) to get: (6 + 2x) + 2x = 0

  • rearrange this to get: 6 + 4x = 0. Simplify to get x = -(6/4). Get the value for x to be: x = -1.5.

  • substitute this x value into equation (b) to get the value for y, hence we get: y + 2(-1.5) = 0; y = 3.

FM
Answered by Faizan M. Maths tutor

9981 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are n sweets in a bag. 6 of the sweets are orange. The rest of the sweets are yellow. Hannah takes a sweet from the bag and eats it. Hannah then takes at another sweet. The probability that Hannah eats two orange sweets is 1/3. Show that n²-n-90=0


How can I calculate the value of a number raised to the power of a fraction, e.g., 9^(3/2)?


Solve this simultaneous equation using the process of elimination: -6x - 2y = 14 3x - 2y = 5


Express the recurring decimal 0.2131313 as a fraction


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences