Top answers

What is the simplified version of ( 2a+4a^2+3a)

Firstly group the like terms to make the expression (5a+4a^2) and then factor out 'a' as it is a common term.This makes the expression ( a(5+4a))
RG
Answered by Rajun G. • Maths tutor
4266 Views

Find the solutions to the simultaneous equations

y - 2x = 3 x 2 + y 2 = 18Step 1- re-arrange the first formula to find y: y = 3 + 2x Step 2- Substitution: x 2 + ( 3 + 2x ) 2 = 18 Step 3- Expand the brackets: ( 3 + 2x )( 3 + 2x ) = 9 + 6x + 6x + 4x 2 x 2 + ...
RH
Answered by Rebecca H. • Maths tutor
3479 Views

Find the roots of the following curve: y = 6x^2 - 4x.

The two terms in the quadratic equation share the factors 2 and x , so these can be brought outside the bracket as shown: y = 2x(3x-2). In order to solve for the roots (where the curve intercepts the x-axis)...
SK
Answered by Sam K. • Maths tutor
3251 Views

Complete the square of X^2 + 4X - 12

X^2 + 4X - 12X^2 + yX + z(x + a)^2 + ba = y/2a = 4/2 = 2b = z - a^2b = -12 -2^2 = -16Therefore: x^2 + 4x - 12 = (x+2)^2 - 16
AR
Answered by Anastasia R. • Maths tutor
3038 Views

Work out the value of (16/81)^3/4

Treat each component separately and break it down...Note that when a number has a power that is a fraction, the numerator acts as a power and the denominator acts as a root(16)^1/4 = 2. Okay, brilliant!So wh...
MT
Answered by Maisie T. • Maths tutor
7067 Views