Find the solutions to the simultaneous equations

y - 2x = 3 x2 + y2 = 18Step 1- re-arrange the first formula to find y: y = 3 + 2x Step 2- Substitution: x2 + ( 3 + 2x )2 = 18 Step 3- Expand the brackets: ( 3 + 2x )( 3 + 2x ) = 9 + 6x + 6x + 4x2 x2 + 9 + 12x + 4x2 = 18 5x2 + 12x + 9 = 18 Step 4- Make the equation equal to zero and factorise: 5x2 + 12x - 9 = 0 ( 5x - 3 ) ( x + 3 ) = 0 Step 5- Solve for x: x = -3 or 3/5 Step 6- Substitute the x values into the original equation to find y: y - 2x = 3 y - 2 ( -3 ) = 3 y + 6 = 3 y = -3 or, y - 2 ( 3/5 ) = 3 y - 6/5 = 3 y = 4 1/5 Answer: x = -3 or 3/5 and y = -3 or 4 1/5

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Factorise 100-x^2


Jo wants to work out the solutions of x^2 + 3x – 5 = 0. Can the solution be worked out?


Solve for x in the following equation using the quadratic formula, completing the square and factoring method: 2x^2-x-1=0


Fully simplify: (y^2 x y^5) / y^3