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Find the stationary points of the curve given by the following function: f(x) = x^2 + 5x + 2

Differentiate the curve to get the gradient function: f'(x)= 2x + 5. Solve for x when f'(x) = 0 --> 2x + 5 = 0, 2x = -5, x = -5/2 Substitute into the original equation to find y: (-2.5)^2 + 5 * -2.5 + 2 =...
TD
Answered by Tutor49585 D. • Maths tutor
4631 Views

Solve this question

2X2 = 4
MK
Answered by Maria K. • Maths tutor
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The curve C has equation x^2 + 2xy + 3y^2 = 4. Find dy/dx.

Here, we have to use implicit differentiation, along with the product rule. Remember that the product rule is (vu)' = vu'+uv'. Moving through the equation we have: x^2+2xy+3y^2 = 4 ==> 2x +2y + 2x*(dy/dx)...
CB
Answered by Chris B. • Maths tutor
12835 Views

How can i add algebraic fractions, such as 1/(1-x) + 2/x

The trick to working out how to do this, is to remember how to add normal fractions! We know 1/8 + 3/8 = 4/8 . The point here is that IF THE DENOMINATORS ARE THE SAME, we can add the numerators. So what abou...
MW
Answered by Matthew W. • Maths tutor
4744 Views

When given an equation in parametric form, how can you figure out dy/dx?

Assuming we are given that x = f(t) and y = g(t), we first differentiate x with respect to t to obtain dx/dt. Then, we differentiate y with respect to t to obtain dy/dt. Much like fractions, we can find dt/d...
DJ
Answered by Dave J. • Maths tutor
3812 Views