Expand and simplify the following equation: 6(x-3) - 4(x-5) = 0

Start off by dealing with the brackets by expanding. The brackets around a part of the equation imply that the entire content of the brackets will be affected by the factor outside of the brackets, in this case multiplied by 6 for the first bracket, and multiplied by -4 for the second. The first bracket gives us "6x - 18" and the second, "-4x+20". Since we included the subtraction sign in the factor which was affecting our bracket, we can just join the two sets of terms together in one expression; "6x-18-4x+20". Simplify and form a final expression. Rearrange the terms so the "x"s are together and the integers are together also, 6x-4x+20-18 = 2x + 2 (END ANSWER)

SH
Answered by Sophia H. Maths tutor

11207 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you factorise a quadratic equation


Rob has a bag with white, black and blue counters. There are twice as many blue counters than there are white. A qaurter of all the counters are black. If there are 5 white counters, how many counters are in the bag.


A-level - How to differentiate e^x where x is more complicated?


Prove that multiplication of two odd numbers produces an odd number.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning