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How do I factorise a quadratic equation?

Firstly , make sure you agree that a quadratic equation is an equation of the form y = ax 2 + bx + c where a , b , c are (real) constants ( a is not 0), and x is the variable. (Note: the equation has an &quo...
GL
Answered by Gemma L. • Maths tutor
5794 Views

differentiate x^3(1+x)^5 with respect for x

First we have to use the product rule, remember that if we have h(x)=f(x)g(x) then h'(x)=f'(x)g(x)+f(x)g'(x).So h'(x) = x^3D[(x+1)^5]+(x+1)^5D[x^3]Completing the unfinished derivatives,h'(x) = x^3[5(x+1)^4]+...
RL
Answered by Robert L. • Maths tutor
4917 Views

solve z^4=2(1+isqrt(3)) giving roots in form r(cos(theta)+isin(theta))

Sorry but it's a little hard to write the question out! I have the working on paper but I can't upload it. Ok so first you need to multiply out the brackets to make it a little easeier to look at and obtain ...
RL
Answered by Robert L. • Maths tutor
6875 Views

Solve for 0=<x<360 : 2((tanx)^2) + ((secx)^2) = 1

First step I would take would make it look less intimidating by converting all components into sin and cos i.e 2(((sinx)/(cosx))^2) + 1/((cosx)^2) = 1 Notice that there is a common denominator of cosx^2 so I...
BP
Answered by Bryan P. • Maths tutor
6015 Views

Find the exact solution to: ln(x) + ln(7) = ln(21)

Log rules: log(a) + log(b) = log(ab) so, in this case, we must find x such that 7x = 21 thus x = 3 similarly, log(a) - log(b) = log(a/b) rearranging the original equation we get: ln(x) = ln(21) - ln(7) so x ...
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Answered by Bryan P. • Maths tutor
7733 Views