differentiate x^3(1+x)^5 with respect for x

First we have to use the product rule, remember that if we have h(x)=f(x)g(x) then h'(x)=f'(x)g(x)+f(x)g'(x).So h'(x) = x^3D[(x+1)^5]+(x+1)^5D[x^3]Completing the unfinished derivatives,h'(x) = x^3[5(x+1)^4]+(x+1)^5[3x^2]Simplifies to.h'(x) = 5x^3(x+1)^4+3x^2(x+1)^5remember that we do the (x+1)^5 in the standard way. 

RL
Answered by Robert L. Maths tutor

3970 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A bag contains beads, 60% of which are green. A student claims that the probability of getting two green beads if the beads aren't replaced is 1/3 as 6/10 * 5/9 is 1/3. Is the student right?


How to derive the formula for a geometric series sum


What is the simplified expression of: 3a - a x 4a + 2a? And what rule do we use to carry out the simplification?


Solve the curve xy=2 and x+y=3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences